245x^2+364x+85=1

Solution for 245x^2+364x+85=1 equation:

245x^2+364x+85=1

We move all terms to the left:

245x^2+364x+85-(1)=0

We add all the numbers together, and all the variables

245x^2+364x+84=0

a = 245; b = 364; c = +84;
Δ = b2-4ac
Δ = 3642-4·245·84
Δ = 50176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{50176}=224$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(364)-224}{2*245}=\frac{-588}{490}
=-1+1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(364)+224}{2*245}=\frac{-140}{490}
=-2/7
$